â„–9623[Quote]
>>9609 (OP)1/0 is infinity, that's literally how division works. Take the second number and see how many times it "fits" into the first one.
10/2 is equal to 5 because you can fit 2 into 10 five times.
So 1/0 is equal to infinity because you can keep fitting zero into one endlessly.
â„–9852[Quote]
>I was playing around with the Fibonacci sequence for fun, and I think it may prove that 1/0 = infinity and 1/inf. = 0 (although I'd need someone with more mathematical know-how to prove it beyond a doubt)
>Sorry for the atrocious picture quality my regular phone is damaged( it fell into my toiled )
>
>I'm not too much of a math wiz ( passed calc. 3 but just barely ), but I'm good enough with pattern recognition
>>Pic rel. (again I apologize for the quality)
>
>I might try to post again later with better quality, but I'm lazy
>
>What are your thoughts, 'teens?
imagine the face of this man who wrote this just for fun
â„–11263[Quote]
File: wilson.jpg 📥︎ (57.44 KB, 1024x767) 26d3b46465ad9b39c912d2d6ddbdb721b52493546b74d6a4468456dcaa90b92b0ImgOps

I too have played with the fibonacci sequence
^Do code tags work here?
[code]
#include <array>
#include <iostream>
template<uint32_t Length>
inline constexpr auto fibonacci = [](){
std::array<std::uint64_t, Length> arr {};
for(std::uint32_t i = 0; i < Length; i++) {
switch(i) {
case 0:
arr[i] = 0;
break;
case 1:
case 2:
arr[i] = 1;
break;
default:
arr[i] = arr[i-1] + arr[i-2];
break;
}
}
return arr;
}();
int main(int argc, char* argv[]) {
auto fibLut = fibonacci<94>;
uint32_t input;
std::cout << "Enter Fibonnacci Position between 1 and 93" << std::endl;
std::cin >> input;
std::cout << "# at position is: " << fibLut[input] << std::endl;
return 0;
}
[/code]
â„–11638[Quote]
Related:
>>8918 (OP)>>7903 (OP)